Base | Representation |
---|---|
bin | 11101110010010011010010… |
… | …111011000000110111011000 |
3 | 122011211111000002222120102002 |
4 | 131302103102323000313120 |
5 | 114132301041022312100 |
6 | 1142340331011500132 |
7 | 36410304066601262 |
oct | 3562232273006730 |
9 | 564744002876362 |
10 | 131000041213400 |
11 | 38816895112387 |
12 | 128388288b7648 |
13 | 5813335250948 |
14 | 244c615c92b32 |
15 | 10229297512d5 |
hex | 7724d2ec0dd8 |
131000041213400 has 48 divisors (see below), whose sum is σ = 317817491302800. Its totient is φ = 50121754897280.
The previous prime is 131000041213399. The next prime is 131000041213409. The reversal of 131000041213400 is 4312140000131.
131000041213400 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×1310000412134002 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131000041213409) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 14239130315 + ... + 14239139514.
It is an arithmetic number, because the mean of its divisors is an integer number (6621197735475).
Almost surely, 2131000041213400 is an apocalyptic number.
131000041213400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131000041213400 is an abundant number, since it is smaller than the sum of its proper divisors (186817450089400).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131000041213400 is a wasteful number, since it uses less digits than its factorization.
131000041213400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28478269868 (or 28478269859 counting only the distinct ones).
The product of its (nonzero) digits is 288, while the sum is 20.
Adding to 131000041213400 its reverse (4312140000131), we get a palindrome (135312181213531).
The spelling of 131000041213400 in words is "one hundred thirty-one trillion, forty-one million, two hundred thirteen thousand, four hundred".
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