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131000042010041 is a prime number
BaseRepresentation
bin11101110010010011010010…
…111110000011010110111001
3122011211111000011111001012022
4131302103102332003112321
5114132301041223310131
61142340331040524225
736410304106426661
oct3562232276032671
9564744004431168
10131000042010041
1138816895606966
1212838829020675
13581333546c429
14244c61601d1a1
15102292985c37b
hex7724d2f835b9

131000042010041 has 2 divisors, whose sum is σ = 131000042010042. Its totient is φ = 131000042010040.

The previous prime is 131000042009987. The next prime is 131000042010049. The reversal of 131000042010041 is 140010240000131.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 130548242944441 + 451799065600 = 11425771^2 + 672160^2 .

It is a cyclic number.

It is not a de Polignac number, because 131000042010041 - 210 = 131000042009017 is a prime.

It is a super-2 number, since 2×1310000420100412 (a number of 29 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (131000042010049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500021005020 + 65500021005021.

It is an arithmetic number, because the mean of its divisors is an integer number (65500021005021).

Almost surely, 2131000042010041 is an apocalyptic number.

It is an amenable number.

131000042010041 is a deficient number, since it is larger than the sum of its proper divisors (1).

131000042010041 is an equidigital number, since it uses as much as digits as its factorization.

131000042010041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 131000042010041 its reverse (140010240000131), we get a palindrome (271010282010172).

The spelling of 131000042010041 in words is "one hundred thirty-one trillion, forty-two million, ten thousand, forty-one".