1310001132020 has 36 divisors (see below), whose sum is σ = 3200145624900. Its totient is φ = 449143244928.

The previous prime is 1310001131993. The next prime is 1310001132031. The reversal of 1310001132020 is 202311000131.

It can be written as a sum of positive squares in 2 ways, for example, as 958918811536 + 351082320484 = 979244^2 + 592522^2 .

It is a super-2 number, since 2×1310001132020² (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (14).

It is a junction number, because it is equal to n+sod(n) for n = 1310001131986 and 1310001132004.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 668366945 + ... + 668368904.

It is an arithmetic number, because the mean of its divisors is an integer number (88892934025).

Almost surely, 2^{1310001132020} is an apocalyptic number.

1310001132020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1310001132020 is an abundant number, since it is smaller than the sum of its proper divisors (1890144492880).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1310001132020 is a wasteful number, since it uses less digits than its factorization.

1310001132020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1336735872 (or 1336735863 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 1310001132020 its reverse (202311000131), we get a palindrome (1512312132151).

The spelling of 1310001132020 in words is "one trillion, three hundred ten billion, one million, one hundred thirty-two thousand, twenty".