Base | Representation |
---|---|
bin | 100111000010101… |
… | …0000101101100011 |
3 | 10101021222222221022 |
4 | 1032011100231203 |
5 | 10140330031034 |
6 | 333553520055 |
7 | 44314555604 |
oct | 11605205543 |
9 | 3337888838 |
10 | 1310002019 |
11 | 6125099a7 |
12 | 30687302b |
13 | 17b52a731 |
14 | c5da5dab |
15 | 7a018b2e |
hex | 4e150b63 |
1310002019 has 2 divisors, whose sum is σ = 1310002020. Its totient is φ = 1310002018.
The previous prime is 1310001971. The next prime is 1310002021. The reversal of 1310002019 is 9102000131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1310002019 - 228 = 1041566563 is a prime.
It is a super-2 number, since 2×13100020192 = 3432210579568152722, which contains 22 as substring.
Together with 1310002021, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 1310001988 and 1310002006.
It is not a weakly prime, because it can be changed into another prime (1310002319) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655001009 + 655001010.
It is an arithmetic number, because the mean of its divisors is an integer number (655001010).
Almost surely, 21310002019 is an apocalyptic number.
1310002019 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310002019 is an equidigital number, since it uses as much as digits as its factorization.
1310002019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 17.
The square root of 1310002019 is about 36193.9500331202. The cubic root of 1310002019 is about 1094.1847434899.
The spelling of 1310002019 in words is "one billion, three hundred ten million, two thousand, nineteen".
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