| Base | Representation |
|---|---|
| bin | 11000011001101001… |
| … | …00111111001101000 |
| 3 | 1020210222000010202212 |
| 4 | 30030310213321220 |
| 5 | 203312101222100 |
| 6 | 10003522544252 |
| 7 | 642426235022 |
| oct | 141464477150 |
| 9 | 36728003685 |
| 10 | 13100023400 |
| 11 | 5612692522 |
| 12 | 2657208088 |
| 13 | 130a023049 |
| 14 | 8c3b65012 |
| 15 | 51a10d635 |
| hex | 30cd27e68 |
13100023400 has 96 divisors (see below), whose sum is σ = 31518220800. Its totient is φ = 5058374400.
The previous prime is 13100023397. The next prime is 13100023403. The reversal of 13100023400 is 432000131.
13100023400 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (13100023397) and next prime (13100023403).
It is a super-2 number, since 2×131000234002 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13100023403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2719394 + ... + 2724206.
It is an arithmetic number, because the mean of its divisors is an integer number (328314800).
Almost surely, 213100023400 is an apocalyptic number.
13100023400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13100023400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15759110400).
13100023400 is an abundant number, since it is smaller than the sum of its proper divisors (18418197400).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13100023400 is a wasteful number, since it uses less digits than its factorization.
13100023400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5299 (or 5290 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 14.
Adding to 13100023400 its reverse (432000131), we get a palindrome (13532023531).
The spelling of 13100023400 in words is "thirteen billion, one hundred million, twenty-three thousand, four hundred".
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