1310002424130 has 64 divisors (see below), whose sum is σ = 3167346094848. Its totient is φ = 346741248000.

The previous prime is 1310002424119. The next prime is 1310002424161. The reversal of 1310002424130 is 314242000131.

It is a super-2 number, since 2×1310002424130² (a number of 25 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1310002424097 and 1310002424106.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 46770130 + ... + 46798130.

It is an arithmetic number, because the mean of its divisors is an integer number (49489782732).

Almost surely, 2^{1310002424130} is an apocalyptic number.

1310002424130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1310002424130 is an abundant number, since it is smaller than the sum of its proper divisors (1857343670718).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1310002424130 is a wasteful number, since it uses less digits than its factorization.

1310002424130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 39531.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 1310002424130 its reverse (314242000131), we get a palindrome (1624244424261).

The spelling of 1310002424130 in words is "one trillion, three hundred ten billion, two million, four hundred twenty-four thousand, one hundred thirty".