13100031231163 has 2 divisors, whose sum is σ = 13100031231164. Its totient is φ = 13100031231162.

The previous prime is 13100031231061. The next prime is 13100031231179. The reversal of 13100031231163 is 36113213000131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13100031231163 is a prime.

It is a super-3 number, since 3×13100031231163³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (13100031231263) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550015615581 + 6550015615582.

It is an arithmetic number, because the mean of its divisors is an integer number (6550015615582).

Almost surely, 2^{13100031231163} is an apocalyptic number.

13100031231163 is a deficient number, since it is larger than the sum of its proper divisors (1).

13100031231163 is an equidigital number, since it uses as much as digits as its factorization.

13100031231163 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 13100031231163 its reverse (36113213000131), we get a palindrome (49213244231294).

The spelling of 13100031231163 in words is "thirteen trillion, one hundred billion, thirty-one million, two hundred thirty-one thousand, one hundred sixty-three".