Base | Representation |
---|---|
bin | 11101110010010011100011… |
… | …000101101010100010111100 |
3 | 122011211111201000100100202111 |
4 | 131302103203011222202330 |
5 | 114132302114441103040 |
6 | 1142340413541103404 |
7 | 36410313602154331 |
oct | 3562234305524274 |
9 | 564744630310674 |
10 | 131000312441020 |
11 | 38816a14224740 |
12 | 128388a36b7b64 |
13 | 58133794b6469 |
14 | 244c63dcd6988 |
15 | 1022943479dea |
hex | 7724e316a8bc |
131000312441020 has 96 divisors (see below), whose sum is σ = 302129663463936. Its totient is φ = 47315932704000.
The previous prime is 131000312441017. The next prime is 131000312441027. The reversal of 131000312441020 is 20144213000131.
It is a super-3 number, since 3×1310003124410203 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Harshad number since it is a multiple of its sum of digits (22).
It is a junction number, because it is equal to n+sod(n) for n = 131000312440982 and 131000312441000.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131000312441027) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 316944814 + ... + 317357866.
It is an arithmetic number, because the mean of its divisors is an integer number (3147183994416).
Almost surely, 2131000312441020 is an apocalyptic number.
131000312441020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131000312441020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (151064831731968).
131000312441020 is an abundant number, since it is smaller than the sum of its proper divisors (171129351022916).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131000312441020 is a wasteful number, since it uses less digits than its factorization.
131000312441020 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 422771 (or 422769 counting only the distinct ones).
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 131000312441020 its reverse (20144213000131), we get a palindrome (151144525441151).
The spelling of 131000312441020 in words is "one hundred thirty-one trillion, three hundred twelve million, four hundred forty-one thousand, twenty".
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