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131000312441020 = 225111519547413053
BaseRepresentation
bin11101110010010011100011…
…000101101010100010111100
3122011211111201000100100202111
4131302103203011222202330
5114132302114441103040
61142340413541103404
736410313602154331
oct3562234305524274
9564744630310674
10131000312441020
1138816a14224740
12128388a36b7b64
1358133794b6469
14244c63dcd6988
151022943479dea
hex7724e316a8bc

131000312441020 has 96 divisors (see below), whose sum is σ = 302129663463936. Its totient is φ = 47315932704000.

The previous prime is 131000312441017. The next prime is 131000312441027. The reversal of 131000312441020 is 20144213000131.

It is a super-3 number, since 3×1310003124410203 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (22).

It is a junction number, because it is equal to n+sod(n) for n = 131000312440982 and 131000312441000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131000312441027) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 316944814 + ... + 317357866.

It is an arithmetic number, because the mean of its divisors is an integer number (3147183994416).

Almost surely, 2131000312441020 is an apocalyptic number.

131000312441020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131000312441020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (151064831731968).

131000312441020 is an abundant number, since it is smaller than the sum of its proper divisors (171129351022916).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131000312441020 is a wasteful number, since it uses less digits than its factorization.

131000312441020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 422771 (or 422769 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 131000312441020 its reverse (20144213000131), we get a palindrome (151144525441151).

The spelling of 131000312441020 in words is "one hundred thirty-one trillion, three hundred twelve million, four hundred forty-one thousand, twenty".

Divisors: 1 2 4 5 10 11 20 22 44 55 110 151 220 302 604 755 1510 1661 3020 3322 6644 8305 9547 16610 19094 33220 38188 47735 95470 105017 190940 210034 413053 420068 525085 826106 1050170 1441597 1652212 2065265 2100340 2883194 4130530 4543583 5766388 7207985 8261060 9087166 14415970 15857567 18174332 22717915 28831940 31715134 45435830 62371003 63430268 79287835 90871660 124742006 158575670 249484012 311855015 317151340 623710030 686081033 1247420060 1372162066 2744324132 3430405165 3943416991 6860810330 7886833982 13721620660 15773667964 19717084955 39434169910 43377586901 78868339820 86755173802 173510347604 216887934505 433775869010 595455965641 867551738020 1190911931282 2381823862564 2977279828205 5954559656410 6550015622051 11909119312820 13100031244102 26200062488204 32750078110255 65500156220510 131000312441020