131000314400231 has 2 divisors, whose sum is σ = 131000314400232. Its totient is φ = 131000314400230.

The previous prime is 131000314400203. The next prime is 131000314400233. The reversal of 131000314400231 is 132004413000131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131000314400231 - 2³⁴ = 130983134531047 is a prime.

It is a super-2 number, since 2×131000314400231² (a number of 29 digits) contains 22 as substring.

Together with 131000314400233, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 131000314400197 and 131000314400206.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131000314400233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500157200115 + 65500157200116.

It is an arithmetic number, because the mean of its divisors is an integer number (65500157200116).

Almost surely, 2^{131000314400231} is an apocalyptic number.

131000314400231 is a deficient number, since it is larger than the sum of its proper divisors (1).

131000314400231 is an equidigital number, since it uses as much as digits as its factorization.

131000314400231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 131000314400231 its reverse (132004413000131), we get a palindrome (263004727400362).

The spelling of 131000314400231 in words is "one hundred thirty-one trillion, three hundred fourteen million, four hundred thousand, two hundred thirty-one".