Search a number
-
+
13100044113293 is a prime number
BaseRepresentation
bin1011111010100001011101…
…1110011101010110001101
31201101100111121011001120212
42332220113132131112031
53204112342243111133
643510024401052205
72521306206466154
oct276502736352615
951340447131525
1013100044113293
1141a0774425865
121576a62327065
137404376719a7
1433408cc8a59b
1517ab676d7148
hexbea1779d58d

13100044113293 has 2 divisors, whose sum is σ = 13100044113294. Its totient is φ = 13100044113292.

The previous prime is 13100044113251. The next prime is 13100044113307. The reversal of 13100044113293 is 39231144000131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8656434921124 + 4443609192169 = 2942182^2 + 2107987^2 .

It is an emirp because it is prime and its reverse (39231144000131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13100044113293 - 26 = 13100044113229 is a prime.

It is a super-2 number, since 2×131000441132932 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13100044113193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550022056646 + 6550022056647.

It is an arithmetic number, because the mean of its divisors is an integer number (6550022056647).

Almost surely, 213100044113293 is an apocalyptic number.

It is an amenable number.

13100044113293 is a deficient number, since it is larger than the sum of its proper divisors (1).

13100044113293 is an equidigital number, since it uses as much as digits as its factorization.

13100044113293 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7776, while the sum is 32.

The spelling of 13100044113293 in words is "thirteen trillion, one hundred billion, forty-four million, one hundred thirteen thousand, two hundred ninety-three".