Search a number
-
+
131001031195 = 526200206239
BaseRepresentation
bin111101000000001000…
…1010001101000011011
3110112010200112220021021
41322000101101220123
54121242230444240
6140103034423311
712315220251436
oct1720021215033
9415120486237
10131001031195
1150614737741
122147bb91b37
13c4793b3198
1464aa40481d
15361ab9a54a
hex1e80451a1b

131001031195 has 4 divisors (see below), whose sum is σ = 157201237440. Its totient is φ = 104800824952.

The previous prime is 131001031181. The next prime is 131001031247. The reversal of 131001031195 is 591130100131.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 591130100131 = 4712577236173.

It is a cyclic number.

It is not a de Polignac number, because 131001031195 - 29 = 131001030683 is a prime.

It is a super-2 number, since 2×1310010311952 (a number of 23 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13100103115 + ... + 13100103124.

It is an arithmetic number, because the mean of its divisors is an integer number (39300309360).

Almost surely, 2131001031195 is an apocalyptic number.

131001031195 is a deficient number, since it is larger than the sum of its proper divisors (26200206245).

131001031195 is an equidigital number, since it uses as much as digits as its factorization.

131001031195 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26200206244.

The product of its (nonzero) digits is 405, while the sum is 25.

The spelling of 131001031195 in words is "one hundred thirty-one billion, one million, thirty-one thousand, one hundred ninety-five".

Divisors: 1 5 26200206239 131001031195