Base | Representation |
---|---|
bin | 11101110010010100001110… |
… | …000010011111111011110011 |
3 | 122011211120120020021010221111 |
4 | 131302110032002133323303 |
5 | 114132310103424001121 |
6 | 1142341013241534151 |
7 | 36410340502114054 |
oct | 3562241602377363 |
9 | 564746506233844 |
10 | 131001033031411 |
11 | 38817253a57994 |
12 | 12838a64aa4357 |
13 | 58134628848ca |
14 | 244c6ab8b072b |
15 | 10229868682e1 |
hex | 77250e09fef3 |
131001033031411 has 2 divisors, whose sum is σ = 131001033031412. Its totient is φ = 131001033031410.
The previous prime is 131001033031409. The next prime is 131001033031457. The reversal of 131001033031411 is 114130330100131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131001033031411 - 21 = 131001033031409 is a prime.
It is a super-2 number, since 2×1310010330314112 (a number of 29 digits) contains 22 as substring.
Together with 131001033031409, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (131001033034411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500516515705 + 65500516515706.
It is an arithmetic number, because the mean of its divisors is an integer number (65500516515706).
Almost surely, 2131001033031411 is an apocalyptic number.
131001033031411 is a deficient number, since it is larger than the sum of its proper divisors (1).
131001033031411 is an equidigital number, since it uses as much as digits as its factorization.
131001033031411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 131001033031411 its reverse (114130330100131), we get a palindrome (245131363131542).
The spelling of 131001033031411 in words is "one hundred thirty-one trillion, one billion, thirty-three million, thirty-one thousand, four hundred eleven".
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