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131001033031411 is a prime number
BaseRepresentation
bin11101110010010100001110…
…000010011111111011110011
3122011211120120020021010221111
4131302110032002133323303
5114132310103424001121
61142341013241534151
736410340502114054
oct3562241602377363
9564746506233844
10131001033031411
1138817253a57994
1212838a64aa4357
1358134628848ca
14244c6ab8b072b
1510229868682e1
hex77250e09fef3

131001033031411 has 2 divisors, whose sum is σ = 131001033031412. Its totient is φ = 131001033031410.

The previous prime is 131001033031409. The next prime is 131001033031457. The reversal of 131001033031411 is 114130330100131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131001033031411 - 21 = 131001033031409 is a prime.

It is a super-2 number, since 2×1310010330314112 (a number of 29 digits) contains 22 as substring.

Together with 131001033031409, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (131001033034411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500516515705 + 65500516515706.

It is an arithmetic number, because the mean of its divisors is an integer number (65500516515706).

Almost surely, 2131001033031411 is an apocalyptic number.

131001033031411 is a deficient number, since it is larger than the sum of its proper divisors (1).

131001033031411 is an equidigital number, since it uses as much as digits as its factorization.

131001033031411 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 324, while the sum is 22.

Adding to 131001033031411 its reverse (114130330100131), we get a palindrome (245131363131542).

The spelling of 131001033031411 in words is "one hundred thirty-one trillion, one billion, thirty-three million, thirty-one thousand, four hundred eleven".