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131001033031457 is a prime number
BaseRepresentation
bin11101110010010100001110…
…000010011111111100100001
3122011211120120020021011000012
4131302110032002133330201
5114132310103424001312
61142341013241534305
736410340502114151
oct3562241602377441
9564746506234005
10131001033031457
1138817253a57a26
1212838a64aa4395
135813462884934
14244c6ab8b0761
151022986868322
hex77250e09ff21

131001033031457 has 2 divisors, whose sum is σ = 131001033031458. Its totient is φ = 131001033031456.

The previous prime is 131001033031411. The next prime is 131001033031493. The reversal of 131001033031457 is 754130330100131.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 129043261197841 + 1957771833616 = 11359721^2 + 1399204^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131001033031457 is a prime.

It is a super-2 number, since 2×1310010330314572 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131001033030457) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500516515728 + 65500516515729.

It is an arithmetic number, because the mean of its divisors is an integer number (65500516515729).

Almost surely, 2131001033031457 is an apocalyptic number.

It is an amenable number.

131001033031457 is a deficient number, since it is larger than the sum of its proper divisors (1).

131001033031457 is an equidigital number, since it uses as much as digits as its factorization.

131001033031457 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11340, while the sum is 32.

Adding to 131001033031457 its reverse (754130330100131), we get a palindrome (885131363131588).

The spelling of 131001033031457 in words is "one hundred thirty-one trillion, one billion, thirty-three million, thirty-one thousand, four hundred fifty-seven".