Base | Representation |
---|---|
bin | 11101110010010100010010… |
… | …101100110110011000110111 |
3 | 122011211120202200102200002220 |
4 | 131302110102230312120313 |
5 | 114132310233434223140 |
6 | 1142341025114133423 |
7 | 36410342441646120 |
oct | 3562242254663067 |
9 | 564746680380086 |
10 | 131001111242295 |
11 | 38817294116988 |
12 | 12838a87121273 |
13 | 5813475b39838 |
14 | 244c6b802d047 |
15 | 102298d666bd0 |
hex | 772512b36637 |
131001111242295 has 64 divisors (see below), whose sum is σ = 255251279932416. Its totient is φ = 56004499998720.
The previous prime is 131001111242233. The next prime is 131001111242327. The reversal of 131001111242295 is 592242111100131.
It is not a de Polignac number, because 131001111242295 - 212 = 131001111238199 is a prime.
It is a super-2 number, since 2×1310011112422952 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 233445801 + ... + 234006290.
It is an arithmetic number, because the mean of its divisors is an integer number (3988301248944).
Almost surely, 2131001111242295 is an apocalyptic number.
131001111242295 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
131001111242295 is a deficient number, since it is larger than the sum of its proper divisors (124250168690121).
131001111242295 is a wasteful number, since it uses less digits than its factorization.
131001111242295 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 467452280.
The product of its (nonzero) digits is 4320, while the sum is 33.
The spelling of 131001111242295 in words is "one hundred thirty-one trillion, one billion, one hundred eleven million, two hundred forty-two thousand, two hundred ninety-five".
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