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131001112033040 = 24519385672234681
BaseRepresentation
bin11101110010010100010010…
…101111110111011100010000
3122011211120202201220211210202
4131302110102233313130100
5114132310234140024130
61142341025143114332
736410342451451364
oct3562242257673420
9564746681824722
10131001112033040
1138817294606a97
1212838a874429a8
135813476055732
14244c6b81972a4
15102298d771145
hex772512bf7710

131001112033040 has 80 divisors (see below), whose sum is σ = 320616441198720. Its totient is φ = 49641217274880.

The previous prime is 131001112033037. The next prime is 131001112033049. The reversal of 131001112033040 is 40330211100131.

It is a tau number, because it is divible by the number of its divisors (80).

It is a super-2 number, since 2×1310011120330402 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is not an unprimeable number, because it can be changed into a prime (131001112033049) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 57504500 + ... + 59739180.

It is an arithmetic number, because the mean of its divisors is an integer number (4007705514984).

Almost surely, 2131001112033040 is an apocalyptic number.

131001112033040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131001112033040 is an abundant number, since it is smaller than the sum of its proper divisors (189615329165680).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131001112033040 is a wasteful number, since it uses less digits than its factorization.

131001112033040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2273280 (or 2273274 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 131001112033040 its reverse (40330211100131), we get a palindrome (171331323133171).

It can be divided in two parts, 13100111 and 2033040, that added together give a palindrome (15133151).

The spelling of 131001112033040 in words is "one hundred thirty-one trillion, one billion, one hundred twelve million, thirty-three thousand, forty".

Divisors: 1 2 4 5 8 10 16 19 20 38 40 76 80 95 152 190 304 380 760 1520 38567 77134 154268 192835 308536 385670 617072 732773 771340 1465546 1542680 2234681 2931092 3085360 3663865 4469362 5862184 7327730 8938724 11173405 11724368 14655460 17877448 22346810 29310920 35754896 42458939 44693620 58621840 84917878 89387240 169835756 178774480 212294695 339671512 424589390 679343024 849178780 1698357560 3396715120 86184942127 172369884254 344739768508 430924710635 689479537016 861849421270 1378959074032 1637513900413 1723698842540 3275027800826 3447397685080 6550055601652 6894795370160 8187569502065 13100111203304 16375139004130 26200222406608 32750278008260 65500556016520 131001112033040