Base | Representation |
---|---|
bin | 11101110010010100010100… |
… | …011100000111111101000000 |
3 | 122011211120211201022122201122 |
4 | 131302110110130013331000 |
5 | 114132310313421142344 |
6 | 1142341032035251412 |
7 | 36410343244616465 |
oct | 3562242434077500 |
9 | 564746751278648 |
10 | 131001140412224 |
11 | 388172a962a765 |
12 | 12838a94a49b68 |
13 | 581347bbb0a54 |
14 | 244c6bbc6366c |
15 | 1022990ec9aee |
hex | 772514707f40 |
131001140412224 has 56 divisors (see below), whose sum is σ = 268719526771200. Its totient is φ = 63298243607040.
The previous prime is 131001140412217. The next prime is 131001140412239. The reversal of 131001140412224 is 422214041100131.
It is a super-3 number, since 3×1310011404122243 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 131001140412193 and 131001140412202.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 45158084 + ... + 47971395.
Almost surely, 2131001140412224 is an apocalyptic number.
It is an amenable number.
131001140412224 is an abundant number, since it is smaller than the sum of its proper divisors (137718386358976).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131001140412224 is an equidigital number, since it uses as much as digits as its factorization.
131001140412224 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 93130231 (or 93130221 counting only the distinct ones).
The product of its (nonzero) digits is 1536, while the sum is 26.
Adding to 131001140412224 its reverse (422214041100131), we get a palindrome (553215181512355).
The spelling of 131001140412224 in words is "one hundred thirty-one trillion, one billion, one hundred forty million, four hundred twelve thousand, two hundred twenty-four".
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