1310012000119 has 2 divisors, whose sum is σ = 1310012000120. Its totient is φ = 1310012000118.

The previous prime is 1310012000051. The next prime is 1310012000149. The reversal of 1310012000119 is 9110002100131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1310012000119 - 2¹³ = 1310011991927 is a prime.

It is a super-2 number, since 2×1310012000119² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1310012000096 and 1310012000105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1310012000149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655006000059 + 655006000060.

It is an arithmetic number, because the mean of its divisors is an integer number (655006000060).

Almost surely, 2^{1310012000119} is an apocalyptic number.

1310012000119 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310012000119 is an equidigital number, since it uses as much as digits as its factorization.

1310012000119 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 19.

The spelling of 1310012000119 in words is "one trillion, three hundred ten billion, twelve million, one hundred nineteen", and thus it is an aban number.