1310012000149 has 2 divisors, whose sum is σ = 1310012000150. Its totient is φ = 1310012000148.

The previous prime is 1310012000119. The next prime is 1310012000161. The reversal of 1310012000149 is 9410002100131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 666819228100 + 643192772049 = 816590^2 + 801993^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310012000149 - 2¹³ = 1310011991957 is a prime.

It is a super-2 number, since 2×1310012000149² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1310012000119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655006000074 + 655006000075.

It is an arithmetic number, because the mean of its divisors is an integer number (655006000075).

Almost surely, 2^{1310012000149} is an apocalyptic number.

It is an amenable number.

1310012000149 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310012000149 is an equidigital number, since it uses as much as digits as its factorization.

1310012000149 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 22.

The spelling of 1310012000149 in words is "one trillion, three hundred ten billion, twelve million, one hundred forty-nine", and thus it is an aban number.