Base | Representation |
---|---|
bin | 1011111010100001110000… |
… | …0101011001110100000100 |
3 | 1201101100200222122012221202 |
4 | 2332220130011121310010 |
5 | 3204113022041300200 |
6 | 43510040202202032 |
7 | 2521311135622121 |
oct | 276503405316404 |
9 | 51340628565852 |
10 | 13100121431300 |
11 | 41a0804034a42 |
12 | 1576a841b3318 |
13 | 74044a6a33a7 |
14 | 334099255748 |
15 | 17ab6e3ab1d5 |
hex | bea1c159d04 |
13100121431300 has 144 divisors (see below), whose sum is σ = 30000779827200. Its totient is φ = 4957794624000.
The previous prime is 13100121431261. The next prime is 13100121431303. The reversal of 13100121431300 is 313412100131.
It is a super-2 number, since 2×131001214313002 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is not an unprimeable number, because it can be changed into a prime (13100121431303) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 137055926 + ... + 137151474.
It is an arithmetic number, because the mean of its divisors is an integer number (208338748800).
Almost surely, 213100121431300 is an apocalyptic number.
13100121431300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13100121431300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15000389913600).
13100121431300 is an abundant number, since it is smaller than the sum of its proper divisors (16900658395900).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13100121431300 is a wasteful number, since it uses less digits than its factorization.
13100121431300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 96582 (or 96575 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 13100121431300 its reverse (313412100131), we get a palindrome (13413533531431).
The spelling of 13100121431300 in words is "thirteen trillion, one hundred billion, one hundred twenty-one million, four hundred thirty-one thousand, three hundred".
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