131001314000 has 320 divisors, whose sum is σ = 349027660800. Its totient is φ = 47374848000.

The previous prime is 131001313991. The next prime is 131001314011. The reversal of 131001314000 is 413100131.

It is a super-2 number, since 2×131001314000² (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 73225106 + ... + 73226894.

It is an arithmetic number, because the mean of its divisors is an integer number (1090711440).

Almost surely, 2^131001314000 is an apocalyptic number.

131001314000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131001314000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (174513830400).

131001314000 is an abundant number, since it is smaller than the sum of its proper divisors (218026346800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131001314000 is a wasteful number, since it uses less digits than its factorization.

131001314000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1919 (or 1903 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 131001314000 its reverse (413100131), we get a palindrome (131414414131).

The spelling of 131001314000 in words is "one hundred thirty-one billion, one million, three hundred fourteen thousand".