Base | Representation |
---|---|
bin | 11000011001101010… |
… | …00101001000011110 |
3 | 1020210222020020000110 |
4 | 30030311011020132 |
5 | 203312114040014 |
6 | 10003525310450 |
7 | 642430244061 |
oct | 141465051036 |
9 | 36728206013 |
10 | 13100143134 |
11 | 5612764481 |
12 | 2657265426 |
13 | 130a0656b0 |
14 | 8c3b968d8 |
15 | 51a133d59 |
hex | 30cd4521e |
13100143134 has 32 divisors (see below), whose sum is σ = 28506592800. Its totient is φ = 3989256192.
The previous prime is 13100143109. The next prime is 13100143159. The reversal of 13100143134 is 43134100131.
It is an interprime number because it is at equal distance from previous prime (13100143109) and next prime (13100143159).
It is a super-2 number, since 2×131001431342 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13100143134.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 858159 + ... + 873290.
It is an arithmetic number, because the mean of its divisors is an integer number (890831025).
Almost surely, 213100143134 is an apocalyptic number.
13100143134 is an abundant number, since it is smaller than the sum of its proper divisors (15406449666).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13100143134 is a wasteful number, since it uses less digits than its factorization.
13100143134 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1731564.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 13100143134 its reverse (43134100131), we get a palindrome (56234243265).
The spelling of 13100143134 in words is "thirteen billion, one hundred million, one hundred forty-three thousand, one hundred thirty-four".
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