131001443130 has 32 divisors (see below), whose sum is σ = 316049568768. Its totient is φ = 34750817600.

The previous prime is 131001443057. The next prime is 131001443149. The reversal of 131001443130 is 31344100131.

It is a super-2 number, since 2×131001443130² (a number of 23 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 131001443097 and 131001443106.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11425461 + ... + 11436920.

It is an arithmetic number, because the mean of its divisors is an integer number (9876549024).

Almost surely, 2^131001443130 is an apocalyptic number.

131001443130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

131001443130 is an abundant number, since it is smaller than the sum of its proper divisors (185048125638).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131001443130 is a wasteful number, since it uses less digits than its factorization.

131001443130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22862582.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 131001443130 its reverse (31344100131), we get a palindrome (162345543261).

The spelling of 131001443130 in words is "one hundred thirty-one billion, one million, four hundred forty-three thousand, one hundred thirty".