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131002131024214 = 2373175606073759
BaseRepresentation
bin11101110010010101001111…
…011111000000100101010110
3122011211200101202022221220121
4131302111033133000211112
5114132314331020233324
61142341314223422154
736410406633650212
oct3562251737004526
9564750352287817
10131002131024214
113881776782115a
121283911075495a
1358135a91b1aa8
14244c773649942
1510229ece545e4
hex77254f7c0956

131002131024214 has 8 divisors (see below), whose sum is σ = 197030014758720. Its totient is φ = 65325459437976.

The previous prime is 131002131024157. The next prime is 131002131024217. The reversal of 131002131024214 is 412420131200131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131002131024217) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 87803036134 + ... + 87803037625.

It is an arithmetic number, because the mean of its divisors is an integer number (24628751844840).

Almost surely, 2131002131024214 is an apocalyptic number.

131002131024214 is a deficient number, since it is larger than the sum of its proper divisors (66027883734506).

131002131024214 is a wasteful number, since it uses less digits than its factorization.

131002131024214 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 175606074134.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 131002131024214 its reverse (412420131200131), we get a palindrome (543422262224345).

The spelling of 131002131024214 in words is "one hundred thirty-one trillion, two billion, one hundred thirty-one million, twenty-four thousand, two hundred fourteen".

Divisors: 1 2 373 746 175606073759 351212147518 65501065512107 131002131024214