131002131024251 has 2 divisors, whose sum is σ = 131002131024252. Its totient is φ = 131002131024250.

The previous prime is 131002131024241. The next prime is 131002131024371. The reversal of 131002131024251 is 152420131200131.

It is a weak prime.

It is an emirp because it is prime and its reverse (152420131200131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131002131024251 - 2¹⁰ = 131002131023227 is a prime.

It is a super-2 number, since 2×131002131024251² (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 131002131024251.

It is not a weakly prime, because it can be changed into another prime (131002131024221) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65501065512125 + 65501065512126.

It is an arithmetic number, because the mean of its divisors is an integer number (65501065512126).

Almost surely, 2^{131002131024251} is an apocalyptic number.

131002131024251 is a deficient number, since it is larger than the sum of its proper divisors (1).

131002131024251 is an equidigital number, since it uses as much as digits as its factorization.

131002131024251 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 131002131024251 its reverse (152420131200131), we get a palindrome (283422262224382).

The spelling of 131002131024251 in words is "one hundred thirty-one trillion, two billion, one hundred thirty-one million, twenty-four thousand, two hundred fifty-one".