Base | Representation |
---|---|
bin | 1011111010100010001011… |
… | …0000101100101111110110 |
3 | 1201101100222210102001221221 |
4 | 2332220202300230233312 |
5 | 3204113234230204332 |
6 | 43510055243100554 |
7 | 2521313665666552 |
oct | 276504260545766 |
9 | 51340883361857 |
10 | 13100233444342 |
11 | 41a0861291000 |
12 | 1576ab581175a |
13 | 740467961ab5 |
14 | 3340aa092862 |
15 | 17ab79135297 |
hex | bea22c2cbf6 |
13100233444342 has 32 divisors (see below), whose sum is σ = 21918330390528. Its totient is φ = 5870783149000.
The previous prime is 13100233444303. The next prime is 13100233444391. The reversal of 13100233444342 is 24344433200131.
It is a super-2 number, since 2×131002334443422 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13100233444298 and 13100233444307.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 34467334 + ... + 34845337.
It is an arithmetic number, because the mean of its divisors is an integer number (684947824704).
Almost surely, 213100233444342 is an apocalyptic number.
13100233444342 is a deficient number, since it is larger than the sum of its proper divisors (8818096946186).
13100233444342 is an equidigital number, since it uses as much as digits as its factorization.
13100233444342 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 69312777 (or 69312755 counting only the distinct ones).
The product of its (nonzero) digits is 82944, while the sum is 34.
Adding to 13100233444342 its reverse (24344433200131), we get a palindrome (37444666644473).
The spelling of 13100233444342 in words is "thirteen trillion, one hundred billion, two hundred thirty-three million, four hundred forty-four thousand, three hundred forty-two".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •