13100234042020 has 24 divisors (see below), whose sum is σ = 27897963202368. Its totient is φ = 5166289480800.

The previous prime is 13100234041957. The next prime is 13100234042033. The reversal of 13100234042020 is 2024043200131.

It is a super-2 number, since 2×13100234042020² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13100234041982 and 13100234042000.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4612757046 + ... + 4612759885.

It is an arithmetic number, because the mean of its divisors is an integer number (1162415133432).

Almost surely, 2^{13100234042020} is an apocalyptic number.

13100234042020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13100234042020 is an abundant number, since it is smaller than the sum of its proper divisors (14797729160348).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13100234042020 is a wasteful number, since it uses less digits than its factorization.

13100234042020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9225517011 (or 9225517009 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 13100234042020 its reverse (2024043200131), we get a palindrome (15124277242151).

The spelling of 13100234042020 in words is "thirteen trillion, one hundred billion, two hundred thirty-four million, forty-two thousand, twenty".