13100312230040 has 64 divisors (see below), whose sum is σ = 33689706062400. Its totient is φ = 4491110435328.

The previous prime is 13100312229997. The next prime is 13100312230079. The reversal of 13100312230040 is 4003221300131.

It is a super-3 number, since 3×13100312230040³ (a number of 40 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a junction number, because it is equal to n+sod(n) for n = 13100312229994 and 13100312230021.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 755702 + ... + 5174138.

It is an arithmetic number, because the mean of its divisors is an integer number (526401657225).

Almost surely, 2^{13100312230040} is an apocalyptic number.

13100312230040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13100312230040 is an abundant number, since it is smaller than the sum of its proper divisors (20589393832360).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13100312230040 is a wasteful number, since it uses less digits than its factorization.

13100312230040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4429044 (or 4429040 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 13100312230040 its reverse (4003221300131), we get a palindrome (17103533530171).

The spelling of 13100312230040 in words is "thirteen trillion, one hundred billion, three hundred twelve million, two hundred thirty thousand, forty".