Base | Representation |
---|---|
bin | 11000011001101011… |
… | …10010110000101110 |
3 | 1020210222120201101112 |
4 | 30030311302300232 |
5 | 203312141030110 |
6 | 10003533312022 |
7 | 642431653004 |
oct | 141465626056 |
9 | 36728521345 |
10 | 13100330030 |
11 | 5612881937 |
12 | 2657335612 |
13 | 130a0cc798 |
14 | 8c3c04a74 |
15 | 51a16e405 |
hex | 30cd72c2e |
13100330030 has 32 divisors (see below), whose sum is σ = 23788961280. Its totient is φ = 5194007200.
The previous prime is 13100330029. The next prime is 13100330059. The reversal of 13100330030 is 3003300131.
13100330030 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 13100329987 and 13100330014.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 588605 + ... + 610455.
It is an arithmetic number, because the mean of its divisors is an integer number (743405040).
Almost surely, 213100330030 is an apocalyptic number.
13100330030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13100330030 is a deficient number, since it is larger than the sum of its proper divisors (10688631250).
13100330030 is a wasteful number, since it uses less digits than its factorization.
13100330030 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 22384.
The product of its (nonzero) digits is 81, while the sum is 14.
Adding to 13100330030 its reverse (3003300131), we get a palindrome (16103630161).
The spelling of 13100330030 in words is "thirteen billion, one hundred million, three hundred thirty thousand, thirty".
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