Base | Representation |
---|---|
bin | 11101110010010110010101… |
… | …111001001110011110110011 |
3 | 122011211210110002010002101211 |
4 | 131302112111321032132303 |
5 | 114132324240422131003 |
6 | 1142342031342340551 |
7 | 36410451126440611 |
oct | 3562262571163663 |
9 | 564753402102354 |
10 | 131003312302003 |
11 | 388182135aa699 |
12 | 128393a028a757 |
13 | 5813736b4c62b |
14 | 244c8464a46b1 |
15 | 1022a6b9e296d |
hex | 772595e4e7b3 |
131003312302003 has 2 divisors, whose sum is σ = 131003312302004. Its totient is φ = 131003312302002.
The previous prime is 131003312302001. The next prime is 131003312302033. The reversal of 131003312302003 is 300203213300131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131003312302003 - 21 = 131003312302001 is a prime.
It is a super-2 number, since 2×1310033123020032 (a number of 29 digits) contains 22 as substring.
Together with 131003312302001, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (131003312302001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65501656151001 + 65501656151002.
It is an arithmetic number, because the mean of its divisors is an integer number (65501656151002).
Almost surely, 2131003312302003 is an apocalyptic number.
131003312302003 is a deficient number, since it is larger than the sum of its proper divisors (1).
131003312302003 is an equidigital number, since it uses as much as digits as its factorization.
131003312302003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 22.
Adding to 131003312302003 its reverse (300203213300131), we get a palindrome (431206525602134).
The spelling of 131003312302003 in words is "one hundred thirty-one trillion, three billion, three hundred twelve million, three hundred two thousand, three".
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