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131003312302003 is a prime number
BaseRepresentation
bin11101110010010110010101…
…111001001110011110110011
3122011211210110002010002101211
4131302112111321032132303
5114132324240422131003
61142342031342340551
736410451126440611
oct3562262571163663
9564753402102354
10131003312302003
11388182135aa699
12128393a028a757
135813736b4c62b
14244c8464a46b1
151022a6b9e296d
hex772595e4e7b3

131003312302003 has 2 divisors, whose sum is σ = 131003312302004. Its totient is φ = 131003312302002.

The previous prime is 131003312302001. The next prime is 131003312302033. The reversal of 131003312302003 is 300203213300131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131003312302003 - 21 = 131003312302001 is a prime.

It is a super-2 number, since 2×1310033123020032 (a number of 29 digits) contains 22 as substring.

Together with 131003312302001, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (131003312302001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65501656151001 + 65501656151002.

It is an arithmetic number, because the mean of its divisors is an integer number (65501656151002).

Almost surely, 2131003312302003 is an apocalyptic number.

131003312302003 is a deficient number, since it is larger than the sum of its proper divisors (1).

131003312302003 is an equidigital number, since it uses as much as digits as its factorization.

131003312302003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 22.

Adding to 131003312302003 its reverse (300203213300131), we get a palindrome (431206525602134).

The spelling of 131003312302003 in words is "one hundred thirty-one trillion, three billion, three hundred twelve million, three hundred two thousand, three".