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1310035122157 is a prime number
BaseRepresentation
bin10011000100000100001…
…011011001011111101101
311122020102121012110220011
4103010010023121133231
5132430422442402112
62441453303053221
7163434614544316
oct23040413313755
94566377173804
101310035122157
11465645745a83
12191a88141211
13966c7161148
144759825160d
1524124e1eaa7
hex131042d97ed

1310035122157 has 2 divisors, whose sum is σ = 1310035122158. Its totient is φ = 1310035122156.

The previous prime is 1310035122133. The next prime is 1310035122173. The reversal of 1310035122157 is 7512215300131.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 850810691236 + 459224430921 = 922394^2 + 677661^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310035122157 - 219 = 1310034597869 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1310035129157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655017561078 + 655017561079.

It is an arithmetic number, because the mean of its divisors is an integer number (655017561079).

Almost surely, 21310035122157 is an apocalyptic number.

It is an amenable number.

1310035122157 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310035122157 is an equidigital number, since it uses as much as digits as its factorization.

1310035122157 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6300, while the sum is 31.

The spelling of 1310035122157 in words is "one trillion, three hundred ten billion, thirty-five million, one hundred twenty-two thousand, one hundred fifty-seven".