Base | Representation |
---|---|
bin | 1011111010100010111010… |
… | …0111110100011010010111 |
3 | 1201101101111122212020211202 |
4 | 2332220232213310122113 |
5 | 3204114141201134111 |
6 | 43510131112223115 |
7 | 2521321633313633 |
oct | 276505647643227 |
9 | 51341448766752 |
10 | 13100432443031 |
11 | 41a095364a72a |
12 | 1576b5039aa9b |
13 | 740499c583bb |
14 | 3340c8693dc3 |
15 | 17ab8b842b3b |
hex | bea2e9f4697 |
13100432443031 has 2 divisors, whose sum is σ = 13100432443032. Its totient is φ = 13100432443030.
The previous prime is 13100432442971. The next prime is 13100432443061. The reversal of 13100432443031 is 13034423400131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13100432443031 - 222 = 13100428248727 is a prime.
It is a super-2 number, since 2×131004324430312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13100432442985 and 13100432443003.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13100432443061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550216221515 + 6550216221516.
It is an arithmetic number, because the mean of its divisors is an integer number (6550216221516).
Almost surely, 213100432443031 is an apocalyptic number.
13100432443031 is a deficient number, since it is larger than the sum of its proper divisors (1).
13100432443031 is an equidigital number, since it uses as much as digits as its factorization.
13100432443031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 13100432443031 its reverse (13034423400131), we get a palindrome (26134855843162).
The spelling of 13100432443031 in words is "thirteen trillion, one hundred billion, four hundred thirty-two million, four hundred forty-three thousand, thirty-one".
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