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131004470131 is a prime number
BaseRepresentation
bin111101000000001111…
…0011001001101110011
3110112010221000121121021
41322000132121031303
54121244121021011
6140103240240311
712315261423463
oct1720036311563
9415127017537
10131004470131
1150616676437
1221481170097
13c47a018562
1464aaa5bba3
15361b129471
hex1e80799373

131004470131 has 2 divisors, whose sum is σ = 131004470132. Its totient is φ = 131004470130.

The previous prime is 131004470123. The next prime is 131004470137. The reversal of 131004470131 is 131074400131.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (131074400131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131004470131 - 23 = 131004470123 is a prime.

It is a super-2 number, since 2×1310044701312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131004470096 and 131004470105.

It is not a weakly prime, because it can be changed into another prime (131004470137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65502235065 + 65502235066.

It is an arithmetic number, because the mean of its divisors is an integer number (65502235066).

Almost surely, 2131004470131 is an apocalyptic number.

131004470131 is a deficient number, since it is larger than the sum of its proper divisors (1).

131004470131 is an equidigital number, since it uses as much as digits as its factorization.

131004470131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1008, while the sum is 25.

Adding to 131004470131 its reverse (131074400131), we get a palindrome (262078870262).

The spelling of 131004470131 in words is "one hundred thirty-one billion, four million, four hundred seventy thousand, one hundred thirty-one".