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1310048983 is a prime number
BaseRepresentation
bin100111000010101…
…1100001011010111
310101022002101100201
41032011130023113
510140333031413
6333554521331
744315142535
oct11605341327
93338071321
101310048983
11612541211
12306896247
1317b545c19
14c5db9155
157a0279dd
hex4e15c2d7

1310048983 has 2 divisors, whose sum is σ = 1310048984. Its totient is φ = 1310048982.

The previous prime is 1310048981. The next prime is 1310048989. The reversal of 1310048983 is 3898400131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1310048983 - 21 = 1310048981 is a prime.

Together with 1310048981, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1310048981) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655024491 + 655024492.

It is an arithmetic number, because the mean of its divisors is an integer number (655024492).

Almost surely, 21310048983 is an apocalyptic number.

1310048983 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310048983 is an equidigital number, since it uses as much as digits as its factorization.

1310048983 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20736, while the sum is 37.

The square root of 1310048983 is about 36194.5988097672. The cubic root of 1310048983 is about 1094.1978189604.

The spelling of 1310048983 in words is "one billion, three hundred ten million, forty-eight thousand, nine hundred eighty-three".