13100530324613 has 2 divisors, whose sum is σ = 13100530324614. Its totient is φ = 13100530324612.

The previous prime is 13100530324601. The next prime is 13100530324669. The reversal of 13100530324613 is 31642303500131.

13100530324613 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11537312742244 + 1563217582369 = 3396662^2 + 1250287^2 .

It is an emirp because it is prime and its reverse (31642303500131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13100530324613 - 2¹⁰ = 13100530323589 is a prime.

It is a super-2 number, since 2×13100530324613² (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13100530324613.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13100530324313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550265162306 + 6550265162307.

It is an arithmetic number, because the mean of its divisors is an integer number (6550265162307).

Almost surely, 2^{13100530324613} is an apocalyptic number.

It is an amenable number.

13100530324613 is a deficient number, since it is larger than the sum of its proper divisors (1).

13100530324613 is an equidigital number, since it uses as much as digits as its factorization.

13100530324613 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 19440, while the sum is 32.

Adding to 13100530324613 its reverse (31642303500131), we get a palindrome (44742833824744).

The spelling of 13100530324613 in words is "thirteen trillion, one hundred billion, five hundred thirty million, three hundred twenty-four thousand, six hundred thirteen".