Base | Representation |
---|---|
bin | 1011111010100011010100… |
… | …1110011000011100101000 |
3 | 1201101101210101022001222002 |
4 | 2332220311032120130220 |
5 | 3204114403030343100 |
6 | 43510150110350132 |
7 | 2521324450003304 |
oct | 276506516303450 |
9 | 51341711261862 |
10 | 13100543215400 |
11 | 41a0a00129643 |
12 | 1576b814bb348 |
13 | 7404b6ba1194 |
14 | 3340d928ad04 |
15 | 17ab964242d5 |
hex | bea35398728 |
13100543215400 has 96 divisors (see below), whose sum is σ = 30525952865760. Its totient is φ = 5228663696640.
The previous prime is 13100543215381. The next prime is 13100543215427. The reversal of 13100543215400 is 451234500131.
13100543215400 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 397777334 + ... + 397810266.
It is an arithmetic number, because the mean of its divisors is an integer number (317978675685).
Almost surely, 213100543215400 is an apocalyptic number.
13100543215400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13100543215400 is an abundant number, since it is smaller than the sum of its proper divisors (17425409650360).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13100543215400 is a wasteful number, since it uses less digits than its factorization.
13100543215400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 37275 (or 37266 counting only the distinct ones).
The product of its (nonzero) digits is 7200, while the sum is 29.
Adding to 13100543215400 its reverse (451234500131), we get a palindrome (13551777715531).
The spelling of 13100543215400 in words is "thirteen trillion, one hundred billion, five hundred forty-three million, two hundred fifteen thousand, four hundred".
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