Base | Representation |
---|---|
bin | 111101000000010001… |
… | …0011110110001001101 |
3 | 110112011000001001011212 |
4 | 1322000202132301031 |
5 | 4121244404311303 |
6 | 140103315224205 |
7 | 12315303505043 |
oct | 1720042366115 |
9 | 415130031155 |
10 | 131005541453 |
11 | 50617238326 |
12 | 214815a8065 |
13 | c47a302087 |
14 | 64aac5a393 |
15 | 361b28bad8 |
hex | 1e8089ec4d |
131005541453 has 2 divisors, whose sum is σ = 131005541454. Its totient is φ = 131005541452.
The previous prime is 131005541449. The next prime is 131005541467. The reversal of 131005541453 is 354145500131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 98748663049 + 32256878404 = 314243^2 + 179602^2 .
It is a cyclic number.
It is not a de Polignac number, because 131005541453 - 22 = 131005541449 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131005541153) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65502770726 + 65502770727.
It is an arithmetic number, because the mean of its divisors is an integer number (65502770727).
Almost surely, 2131005541453 is an apocalyptic number.
It is an amenable number.
131005541453 is a deficient number, since it is larger than the sum of its proper divisors (1).
131005541453 is an equidigital number, since it uses as much as digits as its factorization.
131005541453 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18000, while the sum is 32.
The spelling of 131005541453 in words is "one hundred thirty-one billion, five million, five hundred forty-one thousand, four hundred fifty-three".
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