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131005541453 is a prime number
BaseRepresentation
bin111101000000010001…
…0011110110001001101
3110112011000001001011212
41322000202132301031
54121244404311303
6140103315224205
712315303505043
oct1720042366115
9415130031155
10131005541453
1150617238326
12214815a8065
13c47a302087
1464aac5a393
15361b28bad8
hex1e8089ec4d

131005541453 has 2 divisors, whose sum is σ = 131005541454. Its totient is φ = 131005541452.

The previous prime is 131005541449. The next prime is 131005541467. The reversal of 131005541453 is 354145500131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 98748663049 + 32256878404 = 314243^2 + 179602^2 .

It is a cyclic number.

It is not a de Polignac number, because 131005541453 - 22 = 131005541449 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131005541153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65502770726 + 65502770727.

It is an arithmetic number, because the mean of its divisors is an integer number (65502770727).

Almost surely, 2131005541453 is an apocalyptic number.

It is an amenable number.

131005541453 is a deficient number, since it is larger than the sum of its proper divisors (1).

131005541453 is an equidigital number, since it uses as much as digits as its factorization.

131005541453 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18000, while the sum is 32.

The spelling of 131005541453 in words is "one hundred thirty-one billion, five million, five hundred forty-one thousand, four hundred fifty-three".