Base | Representation |
---|---|
bin | 1011111010100101000100… |
… | …1000100001000111110000 |
3 | 1201101110000000100100112002 |
4 | 2332221101020201013300 |
5 | 3204121332412040422 |
6 | 43510304354153132 |
7 | 2521342163566031 |
oct | 276512110410760 |
9 | 51343000310462 |
10 | 13101011440112 |
11 | 41a1120462812 |
12 | 15770922827a8 |
13 | 74055cbac21b |
14 | 334141530a88 |
15 | 17abc25b2692 |
hex | bea512211f0 |
13101011440112 has 10 divisors (see below), whose sum is σ = 25383209665248. Its totient is φ = 6550505720048.
The previous prime is 13101011440109. The next prime is 13101011440151. The reversal of 13101011440112 is 21104411010131.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 409406607488 + ... + 409406607519.
Almost surely, 213101011440112 is an apocalyptic number.
It is an amenable number.
13101011440112 is a deficient number, since it is larger than the sum of its proper divisors (12282198225136).
13101011440112 is an equidigital number, since it uses as much as digits as its factorization.
13101011440112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 818813215015 (or 818813215009 counting only the distinct ones).
The product of its (nonzero) digits is 96, while the sum is 20.
Adding to 13101011440112 its reverse (21104411010131), we get a palindrome (34205422450243).
The spelling of 13101011440112 in words is "thirteen trillion, one hundred one billion, eleven million, four hundred forty thousand, one hundred twelve".
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