131010121239341 has 2 divisors, whose sum is σ = 131010121239342. Its totient is φ = 131010121239340.

The previous prime is 131010121239317. The next prime is 131010121239353. The reversal of 131010121239341 is 143932121010131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 130836193873225 + 173927366116 = 11438365^2 + 417046^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131010121239341 is a prime.

It is a super-2 number, since 2×131010121239341² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131010121239298 and 131010121239307.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131010121239301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505060619670 + 65505060619671.

It is an arithmetic number, because the mean of its divisors is an integer number (65505060619671).

Almost surely, 2^{131010121239341} is an apocalyptic number.

It is an amenable number.

131010121239341 is a deficient number, since it is larger than the sum of its proper divisors (1).

131010121239341 is an equidigital number, since it uses as much as digits as its factorization.

131010121239341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3888, while the sum is 32.

Adding to 131010121239341 its reverse (143932121010131), we get a palindrome (274942242249472).

The spelling of 131010121239341 in words is "one hundred thirty-one trillion, ten billion, one hundred twenty-one million, two hundred thirty-nine thousand, three hundred forty-one".