Base | Representation |
---|---|
bin | 11000011001110001… |
… | …00000111011010000 |
3 | 1020211000220221221221 |
4 | 30030320200323100 |
5 | 203312331342113 |
6 | 10004000454424 |
7 | 642441013555 |
oct | 141470407320 |
9 | 36730827857 |
10 | 13101043408 |
11 | 5613219902 |
12 | 265761a414 |
13 | 130a2bc3bb |
14 | 8c3d4ca2c |
15 | 51a26098d |
hex | 30ce20ed0 |
13101043408 has 10 divisors (see below), whose sum is σ = 25383271634. Its totient is φ = 6550521696.
The previous prime is 13101043369. The next prime is 13101043433. The reversal of 13101043408 is 80434010131.
It can be written as a sum of positive squares in only one way, i.e., 9585976464 + 3515066944 = 97908^2 + 59288^2 .
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 409407591 + ... + 409407622.
Almost surely, 213101043408 is an apocalyptic number.
It is an amenable number.
13101043408 is a deficient number, since it is larger than the sum of its proper divisors (12282228226).
13101043408 is an equidigital number, since it uses as much as digits as its factorization.
13101043408 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 818815221 (or 818815215 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 13101043408 its reverse (80434010131), we get a palindrome (93535053539).
The spelling of 13101043408 in words is "thirteen billion, one hundred one million, forty-three thousand, four hundred eight".
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