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131011141243309 is a prime number
BaseRepresentation
bin11101110010011101101000…
…100010010001000110101101
3122011212112122200122111212221
4131302131220202101012231
5114132441304124241214
61142345404251555341
736411146132362435
oct3562355042210655
9564775580574787
10131011141243309
1138820570862118
121283aa0615bb51
1358143b3acc592
14244cd8a1612c5
151022d78e9de24
hex7727688911ad

131011141243309 has 2 divisors, whose sum is σ = 131011141243310. Its totient is φ = 131011141243308.

The previous prime is 131011141243291. The next prime is 131011141243351. The reversal of 131011141243309 is 903342141110131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 119220673867684 + 11790467375625 = 10918822^2 + 3433725^2 .

It is an emirp because it is prime and its reverse (903342141110131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131011141243309 - 219 = 131011140719021 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131011141243369) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505570621654 + 65505570621655.

It is an arithmetic number, because the mean of its divisors is an integer number (65505570621655).

Almost surely, 2131011141243309 is an apocalyptic number.

It is an amenable number.

131011141243309 is a deficient number, since it is larger than the sum of its proper divisors (1).

131011141243309 is an equidigital number, since it uses as much as digits as its factorization.

131011141243309 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7776, while the sum is 34.

The spelling of 131011141243309 in words is "one hundred thirty-one trillion, eleven billion, one hundred forty-one million, two hundred forty-three thousand, three hundred nine".