131011204031132 has 24 divisors (see below), whose sum is σ = 250586895000960. Its totient is φ = 59663546426880.

The previous prime is 131011204031131. The next prime is 131011204031143. The reversal of 131011204031132 is 231130402110131.

It is a junction number, because it is equal to n+sod(n) for n = 131011204031098 and 131011204031107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131011204031131) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 31074761657 + ... + 31074765872.

It is an arithmetic number, because the mean of its divisors is an integer number (10441120625040).

Almost surely, 2^{131011204031132} is an apocalyptic number.

It is an amenable number.

131011204031132 is a deficient number, since it is larger than the sum of its proper divisors (119575690969828).

131011204031132 is a wasteful number, since it uses less digits than its factorization.

131011204031132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 62149527581 (or 62149527579 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 131011204031132 its reverse (231130402110131), we get a palindrome (362141606141263).

The spelling of 131011204031132 in words is "one hundred thirty-one trillion, eleven billion, two hundred four million, thirty-one thousand, one hundred thirty-two".