131011231134103 has 2 divisors, whose sum is σ = 131011231134104. Its totient is φ = 131011231134102.

The previous prime is 131011231134073. The next prime is 131011231134109. The reversal of 131011231134103 is 301431132110131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131011231134103 - 2¹³ = 131011231125911 is a prime.

It is a super-2 number, since 2×131011231134103² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131011231134109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505615567051 + 65505615567052.

It is an arithmetic number, because the mean of its divisors is an integer number (65505615567052).

Almost surely, 2^{131011231134103} is an apocalyptic number.

131011231134103 is a deficient number, since it is larger than the sum of its proper divisors (1).

131011231134103 is an equidigital number, since it uses as much as digits as its factorization.

131011231134103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 25.

Adding to 131011231134103 its reverse (301431132110131), we get a palindrome (432442363244234).

The spelling of 131011231134103 in words is "one hundred thirty-one trillion, eleven billion, two hundred thirty-one million, one hundred thirty-four thousand, one hundred three".