131011443223207 has 2 divisors, whose sum is σ = 131011443223208. Its totient is φ = 131011443223206.

The previous prime is 131011443223181. The next prime is 131011443223229. The reversal of 131011443223207 is 702322344110131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131011443223207 is a prime.

It is a super-4 number, since 4×131011443223207⁴ (a number of 58 digits) contains 4444 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131011443221207) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505721611603 + 65505721611604.

It is an arithmetic number, because the mean of its divisors is an integer number (65505721611604).

Almost surely, 2^{131011443223207} is an apocalyptic number.

131011443223207 is a deficient number, since it is larger than the sum of its proper divisors (1).

131011443223207 is an equidigital number, since it uses as much as digits as its factorization.

131011443223207 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24192, while the sum is 34.

Adding to 131011443223207 its reverse (702322344110131), we get a palindrome (833333787333338).

The spelling of 131011443223207 in words is "one hundred thirty-one trillion, eleven billion, four hundred forty-three million, two hundred twenty-three thousand, two hundred seven".