Base | Representation |
---|---|
bin | 1011111010100101110010… |
… | …0100001000110110110110 |
3 | 1201101110111101020021222020 |
4 | 2332221130210020312312 |
5 | 3204122231011331014 |
6 | 43510335405014010 |
7 | 2521350013020435 |
oct | 276513444106666 |
9 | 51343441207866 |
10 | 13101203230134 |
11 | 41a1209748468 |
12 | 1577126554306 |
13 | 740590850646 |
14 | 33415cbb711c |
15 | 17abd43491a9 |
hex | bea5c908db6 |
13101203230134 has 16 divisors (see below), whose sum is σ = 26256210175488. Its totient is φ = 4358100457512.
The previous prime is 13101203230121. The next prime is 13101203230217. The reversal of 13101203230134 is 43103230210131.
It is a super-4 number, since 4×131012032301344 (a number of 54 digits) contains 4444 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2241818302 + ... + 2241824145.
It is an arithmetic number, because the mean of its divisors is an integer number (1641013135968).
Almost surely, 213101203230134 is an apocalyptic number.
13101203230134 is an abundant number, since it is smaller than the sum of its proper divisors (13155006945354).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13101203230134 is a wasteful number, since it uses less digits than its factorization.
13101203230134 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4483642939.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 13101203230134 its reverse (43103230210131), we get a palindrome (56204433440265).
The spelling of 13101203230134 in words is "thirteen trillion, one hundred one billion, two hundred three million, two hundred thirty thousand, one hundred thirty-four".
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