Base | Representation |
---|---|
bin | 1011111010100101110010… |
… | …1100001100010000010000 |
3 | 1201101110111112012112210212 |
4 | 2332221130230030100100 |
5 | 3204122232031404300 |
6 | 43510335522143252 |
7 | 2521350036662234 |
oct | 276513454142020 |
9 | 51343445175725 |
10 | 13101205341200 |
11 | 41a120a95a549 |
12 | 15771271b1b28 |
13 | 74059110c4b2 |
14 | 33415d1a65c4 |
15 | 17abd4614935 |
hex | bea5cb0c410 |
13101205341200 has 30 divisors (see below), whose sum is σ = 31475645833194. Its totient is φ = 5240482136320.
The previous prime is 13101205341181. The next prime is 13101205341221. The reversal of 13101205341200 is 214350210131.
It can be written as a sum of positive squares in 3 ways, for example, as 309509744896 + 12791695596304 = 556336^2 + 3576548^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 16376506277 + ... + 16376507076.
Almost surely, 213101205341200 is an apocalyptic number.
13101205341200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13101205341200 is an abundant number, since it is smaller than the sum of its proper divisors (18374440491994).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13101205341200 is a wasteful number, since it uses less digits than its factorization.
13101205341200 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 32753013371 (or 32753013360 counting only the distinct ones).
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 13101205341200 its reverse (214350210131), we get a palindrome (13315555551331).
The spelling of 13101205341200 in words is "thirteen trillion, one hundred one billion, two hundred five million, three hundred forty-one thousand, two hundred".
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