131012143403142 has 64 divisors (see below), whose sum is σ = 267460558848000. Its totient is φ = 42774577860768.

The previous prime is 131012143403131. The next prime is 131012143403147. The reversal of 131012143403142 is 241304341210131.

It is a super-3 number, since 3×131012143403142³ (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131012143403147) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 48454459 + ... + 51086777.

It is an arithmetic number, because the mean of its divisors is an integer number (4179071232000).

Almost surely, 2^{131012143403142} is an apocalyptic number.

131012143403142 is an abundant number, since it is smaller than the sum of its proper divisors (136448415444858).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131012143403142 is a wasteful number, since it uses less digits than its factorization.

131012143403142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2633265.

The product of its (nonzero) digits is 6912, while the sum is 30.

Adding to 131012143403142 its reverse (241304341210131), we get a palindrome (372316484613273).

The spelling of 131012143403142 in words is "one hundred thirty-one trillion, twelve billion, one hundred forty-three million, four hundred three thousand, one hundred forty-two".