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131012143413973 is a prime number
BaseRepresentation
bin11101110010011110100100…
…010001001111101011010101
3122011212122020112102001120221
4131302132210101033223111
5114133000332203221343
61142350051531554341
736411213021604003
oct3562364421175325
9564778215361527
10131012143413973
1138820a35528838
121283b0458bb9b1
135814513619783
14244d0432b5a73
151022dd6e5d5ed
hex7727a444fad5

131012143413973 has 2 divisors, whose sum is σ = 131012143413974. Its totient is φ = 131012143413972.

The previous prime is 131012143413971. The next prime is 131012143414001. The reversal of 131012143413973 is 379314341210131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 112059860303889 + 18952283110084 = 10585833^2 + 4353422^2 .

It is a cyclic number.

It is not a de Polignac number, because 131012143413973 - 21 = 131012143413971 is a prime.

Together with 131012143413971, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131012143413971) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65506071706986 + 65506071706987.

It is an arithmetic number, because the mean of its divisors is an integer number (65506071706987).

Almost surely, 2131012143413973 is an apocalyptic number.

It is an amenable number.

131012143413973 is a deficient number, since it is larger than the sum of its proper divisors (1).

131012143413973 is an equidigital number, since it uses as much as digits as its factorization.

131012143413973 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 163296, while the sum is 43.

The spelling of 131012143413973 in words is "one hundred thirty-one trillion, twelve billion, one hundred forty-three million, four hundred thirteen thousand, nine hundred seventy-three".