Base | Representation |
---|---|
bin | 11101110010011110100100… |
… | …010100010101010011100111 |
3 | 122011212122020120221012000001 |
4 | 131302132210110111103213 |
5 | 114133000332410122323 |
6 | 1142350052001202131 |
7 | 36411213031515016 |
oct | 3562364424252347 |
9 | 564778216835001 |
10 | 131012144223463 |
11 | 38820a35a30a38 |
12 | 1283b046030347 |
13 | 5814513841069 |
14 | 244d043446a7d |
15 | 1022dd706d3ad |
hex | 7727a45154e7 |
131012144223463 has 2 divisors, whose sum is σ = 131012144223464. Its totient is φ = 131012144223462.
The previous prime is 131012144223439. The next prime is 131012144223511. The reversal of 131012144223463 is 364322441210131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131012144223463 - 217 = 131012144092391 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131012144223413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65506072111731 + 65506072111732.
It is an arithmetic number, because the mean of its divisors is an integer number (65506072111732).
Almost surely, 2131012144223463 is an apocalyptic number.
131012144223463 is a deficient number, since it is larger than the sum of its proper divisors (1).
131012144223463 is an equidigital number, since it uses as much as digits as its factorization.
131012144223463 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 82944, while the sum is 37.
Adding to 131012144223463 its reverse (364322441210131), we get a palindrome (495334585433594).
The spelling of 131012144223463 in words is "one hundred thirty-one trillion, twelve billion, one hundred forty-four million, two hundred twenty-three thousand, four hundred sixty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •