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131012224040177 is a prime number
BaseRepresentation
bin11101110010011110101001…
…000100110011110011110001
3122011212122110011010021221122
4131302132221010303303301
5114133001013323241202
61142350103532032025
736411215021115554
oct3562365104636361
9564778404107848
10131012224040177
1138820a76a97467
121283b068902615
135814527238b9c
14244d04dca269b
151022dde0879a2
hex7727a9133cf1

131012224040177 has 2 divisors, whose sum is σ = 131012224040178. Its totient is φ = 131012224040176.

The previous prime is 131012224040167. The next prime is 131012224040197. The reversal of 131012224040177 is 771040422210131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 74819749325281 + 56192474714896 = 8649841^2 + 7496164^2 .

It is a cyclic number.

It is not a de Polignac number, because 131012224040177 - 222 = 131012219845873 is a prime.

It is not a weakly prime, because it can be changed into another prime (131012224040107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65506112020088 + 65506112020089.

It is an arithmetic number, because the mean of its divisors is an integer number (65506112020089).

Almost surely, 2131012224040177 is an apocalyptic number.

It is an amenable number.

131012224040177 is a deficient number, since it is larger than the sum of its proper divisors (1).

131012224040177 is an equidigital number, since it uses as much as digits as its factorization.

131012224040177 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18816, while the sum is 35.

The spelling of 131012224040177 in words is "one hundred thirty-one trillion, twelve billion, two hundred twenty-four million, forty thousand, one hundred seventy-seven".