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131012224203347 is a prime number
BaseRepresentation
bin11101110010011110101001…
…000101011011101001010011
3122011212122110011102120202222
4131302132221011123221103
5114133001013344001342
61142350103535331255
736411215022365354
oct3562365105335123
9564778404376688
10131012224203347
1138820a77099013
121283b068980b2b
135814527295236
14244d04dd05d2b
151022dde0baed2
hex7727a915ba53

131012224203347 has 2 divisors, whose sum is σ = 131012224203348. Its totient is φ = 131012224203346.

The previous prime is 131012224203319. The next prime is 131012224203379. The reversal of 131012224203347 is 743302422210131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131012224203347 - 216 = 131012224137811 is a prime.

It is a super-2 number, since 2×1310122242033472 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131012224203307) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65506112101673 + 65506112101674.

It is an arithmetic number, because the mean of its divisors is an integer number (65506112101674).

Almost surely, 2131012224203347 is an apocalyptic number.

131012224203347 is a deficient number, since it is larger than the sum of its proper divisors (1).

131012224203347 is an equidigital number, since it uses as much as digits as its factorization.

131012224203347 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48384, while the sum is 35.

Adding to 131012224203347 its reverse (743302422210131), we get a palindrome (874314646413478).

The spelling of 131012224203347 in words is "one hundred thirty-one trillion, twelve billion, two hundred twenty-four million, two hundred three thousand, three hundred forty-seven".