Base | Representation |
---|---|
bin | 11101110010011110101001… |
… | …000101011011101001010011 |
3 | 122011212122110011102120202222 |
4 | 131302132221011123221103 |
5 | 114133001013344001342 |
6 | 1142350103535331255 |
7 | 36411215022365354 |
oct | 3562365105335123 |
9 | 564778404376688 |
10 | 131012224203347 |
11 | 38820a77099013 |
12 | 1283b068980b2b |
13 | 5814527295236 |
14 | 244d04dd05d2b |
15 | 1022dde0baed2 |
hex | 7727a915ba53 |
131012224203347 has 2 divisors, whose sum is σ = 131012224203348. Its totient is φ = 131012224203346.
The previous prime is 131012224203319. The next prime is 131012224203379. The reversal of 131012224203347 is 743302422210131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131012224203347 - 216 = 131012224137811 is a prime.
It is a super-2 number, since 2×1310122242033472 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131012224203307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65506112101673 + 65506112101674.
It is an arithmetic number, because the mean of its divisors is an integer number (65506112101674).
Almost surely, 2131012224203347 is an apocalyptic number.
131012224203347 is a deficient number, since it is larger than the sum of its proper divisors (1).
131012224203347 is an equidigital number, since it uses as much as digits as its factorization.
131012224203347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48384, while the sum is 35.
Adding to 131012224203347 its reverse (743302422210131), we get a palindrome (874314646413478).
The spelling of 131012224203347 in words is "one hundred thirty-one trillion, twelve billion, two hundred twenty-four million, two hundred three thousand, three hundred forty-seven".
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